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a) Divide the 2 consecutive numbers in order to find the ratio 

\frac{-4200}{5000}=-0.84



b) u_{n}=a_{1}(r)^{n-1} is the formula

u_{6}=5000(-0.84)^{6-1}

u_{6}=5000(-0.84)^{5}

u_{6}= -2091.1



c) \sum=\frac{a_{1}}{1-r}

\sum=\frac{5000}{1-(-0.84)}

\sum=\frac{5000}{1.84)}

\sum=2717.4

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